C++ 重建二叉树(递归方法)
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/**
* struct TreeNode {
* int val;
* struct TreeNode *left;
* struct TreeNode *right;
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* };
*/
#include <vector>
class Solution {
public:
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param preOrder int整型vector
* @param vinOrder int整型vector
* @return TreeNode类
*/
TreeNode* reConstructBinaryTree(vector<int>& preOrder, vector<int>& vinOrder) {
// write code here
int n = preOrder.size();
if (!n) {
return nullptr;
} else if (n == 1) {
return new TreeNode(preOrder[0]);
}
auto root = new TreeNode( preOrder[0]);
for (int i = 0; i < vinOrder.size(); i++) {
if (preOrder[0] == vinOrder[i]) {
std::vector<int> leftPreOrder(preOrder.begin() + 1, preOrder.begin() + i + 1);
std::vector<int> leftVInOrder(vinOrder.begin(), vinOrder.begin() + i);
root->left = reConstructBinaryTree(leftPreOrder, leftVInOrder);
std::vector<int> rightPreOrder(preOrder.begin() + i + 1, preOrder.end());
std::vector<int> rightVInOrder(vinOrder.begin() + i + 1, vinOrder.end());
root->right = reConstructBinaryTree(rightPreOrder, rightVInOrder);
break;
}
}
return root;
}
};
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