双极限齐次性(二)、推导二阶非线性多智能体固定时间一致性协议(第二部分)
2.3、证明系统是全局渐进稳定的
证明 z ˙ = ψ \dot z = \psi z˙=ψ 是全局渐进稳定的
选择李雅普诺夫函数
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\begin{aligned} V_1 & = \frac{l_1}{1 + \alpha_1} \sum_{i=1}^N \sum_{j=1}^N p_i a_{ij} |\tilde{x}_i - \tilde{x}_j|^{1 + \alpha_1} + \frac{l_2}{1 + \alpha_2} \sum_{i=1}^N \sum_{j=1}^N p_i a_{ij} |\tilde{x}_i - \tilde{x}_j|^{1 + \alpha_2} \\ V_2 &= c \tilde{x}^T \hat L \tilde{x} \\ V_3 & = \sum_{i=1}^N p_i (\tilde{x}_i + \tilde{v}_i) ^ 2 \end{aligned}
V1V2V3=1+α1l1i=1∑Nj=1∑Npiaij∣x~i−x~j∣1+α1+1+α2l2i=1∑Nj=1∑Npiaij∣x~i−x~j∣1+α2=cx~TL^x~=i=1∑Npi(x~i+v~i)2
对其求导
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\begin{aligned} \dot V_1 &= l_1\sum_{i=1}^N \sum_{j=1}^N p_i a_{ij} \lceil \tilde{x}_i - \tilde{x}_j\rfloor ^{\alpha_1}(\tilde{v}_i - \tilde{v}_j) + l_2 \sum_{i=1}^N \sum_{j=1}^N p_i a_{ij} \lceil \tilde{x}_i - \tilde{x}_j \rfloor^{\alpha_2}(\tilde{v}_i - \tilde{v}_j) \\ \dot V_2 &= 2c\tilde{x}^T \hat L \tilde{v} = 2c\tilde{x}^T \hat L (\tilde{x} + \tilde{v} -\tilde{x}) = 2c\tilde{x}^T \hat L (\tilde{x} + \tilde{v}) - 2c\tilde{x}^T \hat L x \le c(\tilde{x}+\tilde{v})^T \hat L (\tilde{x} + \tilde{v}) - c\tilde{x}^T \hat L \tilde{x} \\ \dot V_3 &= 2 \sum_{i=1}^N p_i (\tilde{x}_i + \tilde{v}_i) (\tilde{v}_i + {\dot {\tilde{v}}}_i) = 2 \sum_{i=1}^N p_i (\tilde{x}_i + \tilde{v}_i) (\tilde{v}_i + u_i + f(x_i,v_i) - \sum_{j=1}^N p_j f(x_j,v_j)) \end{aligned}
V˙1V˙2V˙3=l1i=1∑Nj=1∑Npiaij⌈x~i−x~j⌋α1(v~i−v~j)+l2i=1∑Nj=1∑Npiaij⌈x~i−x~j⌋α2(v~i−v~j)=2cx~TL^v~=2cx~TL^(x~+v~−x~)=2cx~TL^(x~+v~)−2cx~TL^x≤c(x~+v~)TL^(x~+v~)−cx~TL^x~=2i=1∑Npi(x~i+v~i)(v~i+v~˙i)=2i=1∑Npi(x~i+v~i)(v~i+ui+f(xi,vi)−j=1∑Npjf(xj,vj))
推导
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\begin{aligned} 2 \sum_{i=1}^N p_i (\tilde{x}_i + \tilde{v}_i) v_i &= 2 \sum_{i=1}^N p_i (\tilde{x}_i + v_i) (\tilde{x}_i + v_i - \tilde{x}_i) \\ &\le 2 p_{max} \sum_{i=1}^N (\tilde{x}_i + \tilde{v}_i)^2 + 2 p_{max} \sum_{i=1}^N |\tilde{x}_i + \tilde{v}_i||\tilde{x}_i| \\ &\le 2 p_{max} (\tilde{x} + \tilde{v})^T(\tilde{x} + \tilde{v}) + 2p_{max} (\tilde{x} + \tilde{v})^T x\\ &\le 2 p_{max} (\tilde{x} + \tilde{v})^T(\tilde{x} + \tilde{v})+ p_{max} \tilde{x}^T \tilde{x} + p_{max} (\tilde{x} + \tilde{v})^T \tilde{x} \\ &\le 3 p_{max} (\tilde{x} + \tilde{v})^T(\tilde{x} + \tilde{v})+ p_{max} \tilde{x}^T \tilde{x} \end{aligned}
2i=1∑Npi(x~i+v~i)vi=2i=1∑Npi(x~i+vi)(x~i+vi−x~i)≤2pmaxi=1∑N(x~i+v~i)2+2pmaxi=1∑N∣x~i+v~i∣∣x~i∣≤2pmax(x~+v~)T(x~+v~)+2pmax(x~+v~)Tx≤2pmax(x~+v~)T(x~+v~)+pmaxx~Tx~+pmax(x~+v~)Tx~≤3pmax(x~+v~)T(x~+v~)+pmaxx~Tx~
推导
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f(xi,vi)−∑j=1Npjf(xj,vj) 部分,由于
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\sum_{i=1}^N p_i (x_i + v_i) = 0
∑i=1Npi(xi+vi)=0, 可得
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\sum_{i=1}^N p_i (x_i + v_i) (f(\bar x,\bar v) - \sum_{j=1}^N p_j f(x_j,v_j)) = 0
∑i=1Npi(xi+vi)(f(xˉ,vˉ)−∑j=1Npjf(xj,vj))=0 。基于假设1可得
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\begin{aligned} & 2\sum_{i=1}^N p_i (\tilde{x}_i + \tilde{v}_i) (f(x_i,v_i) - \sum_{j=1}^N p_j f(x_j,v_j)) \\ & = 2\sum_{i=1}^N p_i (\tilde{x}_i + \tilde{v}_i) (f(x_i,v_i) - f(\bar x, \bar v)) \\ & = 2 \rho p_{max} \sum_{i=1}^N |\tilde{x}_i - \tilde{v}_i|(|\tilde{x}_i| + |\tilde{v}_i|) \\ &= 2 \rho p_{max} \sum_{i=1}^N |\tilde{x}_i - \tilde{v}_i|(|\tilde{x}_i| + |\tilde{v}_i + \tilde{x}_i - \tilde{x}_i|) \\ &= 2\rho p_{max} \tilde{x}^T \tilde{x} + 4 \rho p_{max} (\tilde{x} + \tilde{v})^T(\tilde{x} + \tilde{v}) \end{aligned}
2i=1∑Npi(x~i+v~i)(f(xi,vi)−j=1∑Npjf(xj,vj))=2i=1∑Npi(x~i+v~i)(f(xi,vi)−f(xˉ,vˉ))=2ρpmaxi=1∑N∣x~i−v~i∣(∣x~i∣+∣v~i∣)=2ρpmaxi=1∑N∣x~i−v~i∣(∣x~i∣+∣v~i+x~i−x~i∣)=2ρpmaxx~Tx~+4ρpmax(x~+v~)T(x~+v~)
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\begin{aligned} 2 \sum_{i=1}^N p_i (\tilde{x}_i + \tilde{v}_i) u_{3i} &= -2 k \sum_{i=1}^N\sum_{j=1}^N p_i a_{ij} (\tilde{x}_i + \tilde{v}_i) (\tilde{x}_i + \tilde{v}_i - \tilde{x}_j - \tilde{v}_j) \\ &= - k \sum_{i=1}^N\sum_{j=1}^N p_i a_{ij} (\tilde{x}_i + \tilde{v}_i - \tilde{x}_j - \tilde{v}_j)^2 \\ &= -2 k (\tilde{x} + \tilde{v})^T \hat L (\tilde{x} + \tilde{v}) \end{aligned}
2i=1∑Npi(x~i+v~i)u3i=−2ki=1∑Nj=1∑Npiaij(x~i+v~i)(x~i+v~i−x~j−v~j)=−ki=1∑Nj=1∑Npiaij(x~i+v~i−x~j−v~j)2=−2k(x~+v~)TL^(x~+v~)
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\begin{aligned} & 2 \sum_{i=1}^N p_i (\tilde{x}_i + \tilde{v}_i) (u_{1i} + u_{2i}) \\ & = -2 k \sum_{i=1}^N p_i a_{ij} (\tilde{x}_i + \tilde{v}_i) (l_1 \lceil x_i - x_j \rfloor^{\alpha_1} + l_1 \lceil v_i - v_j \rfloor^{\alpha_1'} + l_2 \lceil x_i - x_j \rfloor^{\alpha_2} + l_2 \lceil v_i - v_j \rfloor^{\alpha_2'}) \\ & = -2 k \sum_{i=1}^N p_i a_{ij} \tilde{x}_i (l_1 \lceil x_i - x_j \rfloor^{\alpha_1} + l_1 \lceil v_i - v_j \rfloor^{\alpha_1'} + l_2 \lceil x_i - x_j \rfloor^{\alpha_2} + l_2 \lceil v_i - v_j \rfloor^{\alpha_2'}) \\ & \ \ \ \ - 2 k \sum_{i=1}^N p_i a_{ij} \tilde{v}_i (l_1 \lceil x_i - x_j \rfloor^{\alpha_1} + l_1 \lceil v_i - v_j \rfloor^{\alpha_1'} + l_2 \lceil x_i - x_j \rfloor^{\alpha_2} + l_2 \lceil v_i - v_j \rfloor^{\alpha_2'}) \\ & = -l_1 \sum_{i=1}^N \sum_{j=1}^N p_i a_{ij} |\tilde{x}_i - \tilde{x}_j|^{1+\alpha_1} -l_2 \sum_{i=1}^N \sum_{j=1}^N p_i a_{ij} |\tilde{x}_i - \tilde{x}_j|^{1+\alpha_2} \\ & \ \ \ \ -l_1 \sum_{i=1}^N \sum_{j=1}^N p_i a_{ij} |\tilde{v}_i - \tilde{v}_j|^{1+\alpha_1'} -l_2 \sum_{i=1}^N \sum_{j=1}^N p_i a_{ij} |\tilde{v}_i - \tilde{v}_j|^{1+\alpha_2'} \\ & \ \ \ \ -l_1 \sum_{i=1}^N \sum_{j=1}^N p_i a_{ij} \lceil \tilde{x}_i - \tilde{x}_j \rfloor ^ {\alpha_1}(\tilde{v}_i - \tilde{v}_j ) -l_2 \sum_{i=1}^N \sum_{j=1}^N p_i a_{ij} \lceil \tilde{x}_i - \tilde{x}_j \rfloor ^ {\alpha_2}(\tilde{v}_i - \tilde{v}_j ) \\ & \ \ \ \ -l_1 \sum_{i=1}^N \sum_{j=1}^N p_i a_{ij} \lceil \tilde{v}_i - \tilde{v}_j \rfloor ^ {\alpha_1'}(\tilde{x}_i - \tilde{x}_j ) -l_2 \sum_{i=1}^N \sum_{j=1}^N p_i a_{ij} \lceil \tilde{v}_i - \tilde{v}_j \rfloor ^ {\alpha_2'}(\tilde{x}_i - \tilde{x}_j ) \\ \end{aligned}
2i=1∑Npi(x~i+v~i)(u1i+u2i)=−2ki=1∑Npiaij(x~i+v~i)(l1⌈xi−xj⌋α1+l1⌈vi−vj⌋α1′+l2⌈xi−xj⌋α2+l2⌈vi−vj⌋α2′)=−2ki=1∑Npiaijx~i(l1⌈xi−xj⌋α1+l1⌈vi−vj⌋α1′+l2⌈xi−xj⌋α2+l2⌈vi−vj⌋α2′) −2ki=1∑Npiaijv~i(l1⌈xi−xj⌋α1+l1⌈vi−vj⌋α1′+l2⌈xi−xj⌋α2+l2⌈vi−vj⌋α2′)=−l1i=1∑Nj=1∑Npiaij∣x~i−x~j∣1+α1−l2i=1∑Nj=1∑Npiaij∣x~i−x~j∣1+α2 −l1i=1∑Nj=1∑Npiaij∣v~i−v~j∣1+α1′−l2i=1∑Nj=1∑Npiaij∣v~i−v~j∣1+α2′ −l1i=1∑Nj=1∑Npiaij⌈x~i−x~j⌋α1(v~i−v~j)−l2i=1∑Nj=1∑Npiaij⌈x~i−x~j⌋α2(v~i−v~j) −l1i=1∑Nj=1∑Npiaij⌈v~i−v~j⌋α1′(x~i−x~j)−l2i=1∑Nj=1∑Npiaij⌈v~i−v~j⌋α2′(x~i−x~j)
由引理4(也是一个缩放不等式)以及参数关系
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\begin{aligned} & \ \ \ \ -l_1 \sum_{i=1}^N \sum_{j=1}^N p_i a_{ij} \lceil \tilde{v}_i - \tilde{v}_j \rfloor ^ {\alpha_1'}(\tilde{x}_i - \tilde{x}_j ) \\ & \le l_1 \sum_{i=1}^N \sum_{j=1}^N p_i a_{ij} | \tilde{v}_i - \tilde{v}_j | ^ {\alpha_1'}|\tilde{x}_i - \tilde{x}_j | \\ & \le l_1 \sum_{i=1}^N \sum_{j=1}^N p_i a_{ij} \left(\frac{\alpha_1'}{1+\alpha_1'}|\tilde{v}_i - \tilde{v}_j | ^ {1 + \alpha_1'}+ \frac{1}{1+\alpha_1'} |\tilde{x}_i + \tilde{x}_j | ^ {1 + \alpha_1'} \right) \\ & \le l_1 \sum_{i=1}^N \sum_{j=1}^N p_i a_{ij} \left(\frac{\alpha_1'}{1+\alpha_1'}|\tilde{v}_i - \tilde{v}_j | ^ {1 + \alpha_1'}+ \frac{1}{1+\alpha_1'} |\tilde{x}_i + \tilde{x}_j | ^ {1 + \alpha_1} + \frac{1}{1+\alpha_1'} |\tilde{x}_i + \tilde{x}_j | ^ {2} \right) \\ \end{aligned}
−l1i=1∑Nj=1∑Npiaij⌈v~i−v~j⌋α1′(x~i−x~j)≤l1i=1∑Nj=1∑Npiaij∣v~i−v~j∣α1′∣x~i−x~j∣≤l1i=1∑Nj=1∑Npiaij(1+α1′α1′∣v~i−v~j∣1+α1′+1+α1′1∣x~i+x~j∣1+α1′)≤l1i=1∑Nj=1∑Npiaij(1+α1′α1′∣v~i−v~j∣1+α1′+1+α1′1∣x~i+x~j∣1+α1+1+α1′1∣x~i+x~j∣2)
和上面一样,同样可得
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\begin{aligned} & \ \ \ \ -l_1 \sum_{i=1}^N \sum_{j=1}^N p_i a_{ij} \lceil \tilde{v}_i - \tilde{v}_j \rfloor ^ {\alpha_2'}(\tilde{x}_i - \tilde{x}_j ) \\ & \le l_1 \sum_{i=1}^N \sum_{j=1}^N p_i a_{ij} \left(\frac{\alpha_2'}{1+\alpha_2'}|\tilde{v}_i - \tilde{v}_j | ^ {1 + \alpha_2'}+ \frac{1}{1+\alpha_2'} |\tilde{x}_i + \tilde{x}_j | ^ {1 + \alpha_2} + \frac{1}{1+\alpha_2'} |\tilde{x}_i + \tilde{x}_j | ^ {2} \right) \\ \end{aligned}
−l1i=1∑Nj=1∑Npiaij⌈v~i−v~j⌋α2′(x~i−x~j)≤l1i=1∑Nj=1∑Npiaij(1+α2′α2′∣v~i−v~j∣1+α2′+1+α2′1∣x~i+x~j∣1+α2+1+α2′1∣x~i+x~j∣2)
带入
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\begin{aligned} & \ \ \ \ 2 \sum_{i=1}^N p_i (\tilde{x}_i + \tilde{v}_i) (u_{1i} + u_{2i}) \\ & \le -l_1 \sum_{i=1}^N \sum_{j=1}^N p_i a_{ij} \lceil \tilde{x}_i - \tilde{x}_j \rfloor ^ {\alpha_1}(\tilde{v}_i - \tilde{v}_j ) -l_2 \sum_{i=1}^N \sum_{j=1}^N p_i a_{ij} \lceil \tilde{x}_i - \tilde{x}_j \rfloor ^ {\alpha_2}(\tilde{v}_i - \tilde{v}_j ) \\ & \ \ \ \ + \frac{l_1}{1+\alpha_1'} \sum_{i=1}^N\sum_{j=1}^N p_i a_{ij} |\tilde{x}_i - \tilde{x}_j|^2 + \frac{l_2}{1+\alpha_2'} \sum_{i=1}^N\sum_{j=1}^N p_i a_{ij} |\tilde{x}_i - \tilde{x}_j|^2 \\ & \le -l_1 \sum_{i=1}^N \sum_{j=1}^N p_i a_{ij} \lceil \tilde{x}_i - \tilde{x}_j \rfloor ^ {\alpha_1}(\tilde{v}_i - \tilde{v}_j ) -l_2 \sum_{i=1}^N \sum_{j=1}^N p_i a_{ij} \lceil \tilde{x}_i - \tilde{x}_j \rfloor ^ {\alpha_2}(\tilde{v}_i - \tilde{v}_j ) \\ & \ \ \ \ + \frac{2l_1}{1+\alpha_1'} \tilde{x} ^ T \hat L \tilde{x} + \frac{2l_2}{1+\alpha_2'} \tilde{x} ^ T \hat L \tilde{x} \end{aligned}
2i=1∑Npi(x~i+v~i)(u1i+u2i)≤−l1i=1∑Nj=1∑Npiaij⌈x~i−x~j⌋α1(v~i−v~j)−l2i=1∑Nj=1∑Npiaij⌈x~i−x~j⌋α2(v~i−v~j) +1+α1′l1i=1∑Nj=1∑Npiaij∣x~i−x~j∣2+1+α2′l2i=1∑Nj=1∑Npiaij∣x~i−x~j∣2≤−l1i=1∑Nj=1∑Npiaij⌈x~i−x~j⌋α1(v~i−v~j)−l2i=1∑Nj=1∑Npiaij⌈x~i−x~j⌋α2(v~i−v~j) +1+α1′2l1x~TL^x~+1+α2′2l2x~TL^x~
结合
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V˙3 可得
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\begin{aligned} \dot V & \le (-c + \frac{2l_1}{1+\alpha_1'}+\frac{2l_2}{1+\alpha_2'})\tilde{x} ^ T \hat L \tilde{x} + (2\rho + 1)p_{max} \tilde{x} ^ T \tilde{x} \\ & \ \ \ \ + (-2k + c)(\tilde{x} + \tilde{v}) ^ T \hat L (\tilde{x} + \tilde{v}) + (3 + 4\rho)p_{max} (\tilde{x} + \tilde{v})^T(\tilde{x} + \tilde{v}) \\ & \le -((2\rho + 1)p_{max} + l_3)/K \tilde{x} ^ T \hat L \tilde{x} + (2\rho + 1)p_{max} \tilde{x} ^ T \tilde{x} \\ & \ \ \ \ -((4\rho + 3)p_{max} + l_4)/K (\tilde{x} + \tilde{v})^ T \hat L (\tilde{x} + \tilde{v}) + (3 + 4\rho)p_{max} (\tilde{x} + \tilde{v})^T(\tilde{x} + \tilde{v}) \\ & \le -l_3 \tilde{x}^T \tilde{x} - l_4 (\tilde{x} + \tilde{v})^T (\tilde{x} + \tilde{v}) \\ & \le 0 \end{aligned}
V˙≤(−c+1+α1′2l1+1+α2′2l2)x~TL^x~+(2ρ+1)pmaxx~Tx~ +(−2k+c)(x~+v~)TL^(x~+v~)+(3+4ρ)pmax(x~+v~)T(x~+v~)≤−((2ρ+1)pmax+l3)/Kx~TL^x~+(2ρ+1)pmaxx~Tx~ −((4ρ+3)pmax+l4)/K(x~+v~)TL^(x~+v~)+(3+4ρ)pmax(x~+v~)T(x~+v~)≤−l3x~Tx~−l4(x~+v~)T(x~+v~)≤0
这里用到了引理5,证明到最后一步就用到了参数定义时的不等式,我们发现这个 证明也是利用了巧妙的参数。到这里证明了
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z=ψ 是全局渐进稳定的,也就证明了系统是全局固定时间稳定的。
只能说,精彩!!!
三、仿真
仿真不再做了,从这个控制律的形式也能看出来,效果一定很好,这里难的是证明他的固定时间收敛性,更多的信息可以参考原文
四、参考文献
[1] H. Hong, W. Yu, J. Fu, and X. Yu, “A Novel Class of Distributed Fixed-Time Consensus Protocols for Second-Order Nonlinear and Disturbed Multi-Agent Systems,” IEEE Trans. Netw. Sci. Eng., vol. 6, no. 4, pp. 760–772, Oct. 2019, doi: 10.1109/TNSE.2018.2873060.
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