目录

一、问题：

二、思想：

三、代码：

一、问题：

hive sql实现查询连续n天登陆的用户

二、思想：

1、选出用户id，以及登陆日期，去重

2、窗口函数按照用户id分组，登陆日期不重复排序

3、date_sub归一化登陆日期

4、按照用户id和归一化后的日期 计算 登陆日期 的数量

三、代码：

select distinct user_id
from (
    select user_id
        , continue_date
        , count(login_date) as continue_day_cnt
    from (
        select user_id
            , login_date
            , date_sub(login_date,row_number() over(partition by user_id order by login_date) )as continue_date
        from (
            select user_id
                , substr(login_time, 1, 10) as login_date
            --from dw.dw_user_login_log
            FROM
            (
                select 1 as user_id
                    ,'2020-10-04' as login_date
                union all 
                select 1 as user_id
                    ,'2020-10-05' as login_date
                union all 
                select 1 as user_id
                    ,'2020-10-06' as login_date
                union all 
                select 1 as user_id
                    ,'2020-10-07' as login_date
            ) t1
            where 1 = 1
            group by user_id
                , substr(login_time, 1, 10)
        ) t
    ) m
    where 1 = 1
    group by user_id
        , continue_date
    having count(login_date) >= 3  -- 连续3天登录，根据业务场景调整这一数值
) x ;